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Why did you not include an
inverted cone as in some bin bottoms? This might be done,
but the effort did not seem worth the little use envisioned.
Same with height and width limited walls, which was the initial
intent. The infinite walls are much easier for the user to input
and little is lost by doing it that way.
To handle cone bottoms:
- Divide the bin in two sections
parting at the cone joint.
- Let PileV calculate the total live
volume of both parts using the full height of the bin.
- Record the live volume. Then let
PileV calculate the upper section.
- Record the total volume
of this section. Then hand calculate the dead storage from the
drawhole to the cone joint, if any, and add it to the total
storage.
Unlike an inverted cone, an
inverted pyramid with four sloping walls is possible to calculate
by entering the bin bottom as walls. Then it must be determined
that the infinite extension of the walls causes no errors. The
conical bottom alone can be examined by using level limits, (See
the Run Calc tab).
Multiple drawholes may be contained
at the bottom of the walls. For multiple pyramid bottoms, use a
procedure similar to the cone bottoms above.
Large storage structures with
multiple regularly spaced drawholes can be calculated by isolating
typical drawholes with imaginary walls placed between drawholes
and then adding the results. See the sample calculation records
that are included.
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